On Jun 11, 2012, at 05:50 , Steven Nunez wrote:
(defun algorithm-name (model)
"Returns the algorithm for the model"
(stp:filter-recursively (stp:of-name "algorithmName" (stp:namespace-uri model)) model))
(defun algorithm-name (model)
(xpath:string-value (xpath:evaluate "//RegressionModel/@algorithmName" model))))
(defun model-coefficient-list (model)
(let ((regression-model-node (xpath:first-node (xpath:evaluate "//RegressionModel" model)))
(*read-eval* nil))
`(,(xpath:string-value (xpath:evaluate "@modelName" regression-model-node))
,@(xpath:map-node-set->list
(lambda (node)
(list
(xpath:string-value (xpath:evaluate "@name" node))
;; note: xpath:number-value may work here, depending on
;; your implementation... does not work with Lispworks
;; 6.1 under Mac OS X
(read-from-string (xpath:string-value (xpath:evaluate "@coefficient" node)))))
(xpath:evaluate "RegressionTable/NumericPredictor" regression-model-node))))))
#||
(defparameter *model*
(cxml:parse #p"/Users/raw/Desktop/polynomial-regression.xml" (cxml-stp:make-builder)))
(cxml-stp:serialize *model* (cxml:make-string-sink :indentation 4))
(algorithm-name *model*)
(model-coefficient-list *model*)
||#
;;;;;;;;;;;;;;;;;;;;;;;;;;;;;;
Notes:
1) I'm not sure that model-coefficient-list does what you need.
2) It might be appropriate to use cxml-stp:attribute-value instead of xpath:string-value/xpath:evaluate.
3) Since there are multiple coefficients with the same name (where some have an "exponent" attribute), I guess you'd either need to filter out some of the coefficients, build names that somehow incorporate the exponent, or add the exponent to the list structure returned.
Hope this helps.